Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 58: 106

Answer

$\dfrac{5}{28}$

Work Step by Step

The given expression, $ \left( \dfrac{-2}{7} \right)\left( \dfrac{5}{-8} \right) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{-2(5)}{7(-8)} \\\\= \dfrac{-10}{-56} \\\\= \dfrac{\cancel{-2}\cdot5}{\cancel{-2}\cdot28} \\\\= \dfrac{5}{28} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.