Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set - Page 66: 71

Answer

$-3$

Work Step by Step

Substituting $ t $ with $ -2 $, then the given expression, $ 24\div t^3 $, evaluates to \begin{array}{l} 24\div (-2)^3 \\\\= 24\div (-8) \\\\= -3 .\end{array}
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