Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.1 - Linear Equations in One Variable - 1.1 Exercises - Page 52: 56

Answer

B.

Work Step by Step

The expression $0.06(10-x)(100)$ is equivalent to: $0.06(10-x)(100)$ $(10-x)0.06(100)$ $(10-x)6$ $6*10-6x$ $60-6x$ This matches answer B.
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