Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.1 - Linear Equations in One Variable - 1.1 Exercises - Page 52: 73

Answer

x = -10

Work Step by Step

1. Given: 0.006x - 0.02x + 0.03 = 0.008x + 0.25 2. Multiply both sides by 10 to the 3rd power to turn decimals into whole numbers: 1000(0.006x - 0.02x + 0.03) = (0.008x + 0.25)1000 6x - 20x + 30 = 8x + 250 3. Add and subtract: -22x = 220 4. Divide: x = -10 5. Check: 0.006(-10) - 0.02(-10) + 0.03 = 0.008(-10) + 0.25 0.17 = 0.17, so -10 is a correct solution of the equation.
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