Answer
$\frac{7}{3}$
Work Step by Step
$\frac{(2+4)^2+(-1)^5}{12\div2\times3-3}$
$\frac{36-1}{6\times3-3}$
$\frac{35}{18-3}$
$\frac{35}{15}$
$\frac{7}{3}$
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