Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Review - Page 44: 69

Answer

$\dfrac{5}{7}$

Work Step by Step

Using order of operations, the expression $ \dfrac{(4-9)+4-9}{10-12\div4\cdot8} $ simplifies to \begin{array}{l} \dfrac{-5+4-9}{10-3\cdot8} \\\\= \dfrac{-1-9}{10-24} \\\\= \dfrac{-10}{-14} \\\\= \dfrac{5}{7} .\end{array}
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