Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 27: 64

Answer

-6

Work Step by Step

$-10(-\frac{2}{5})-10=(-10\times-\frac{2}{5})-10=(\frac{10\times2}{5})-10=\frac{20}{5}-10=4-10=-6$
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