Answer
-3
Work Step by Step
$\frac{(-1-2)(-3^{2})}{-6-3}=\frac{(-(1+2))\times(-(3^{2}))}{-(6+3)}=\frac{(-3)\times(-(9))}{-9}=\frac{(-3)\times(-9)}{-9}=\frac{27}{-9}=-\frac{27}{9}=-3$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 27: 68
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