Answer
$K=-23$
Work Step by Step
We are given the equation $\frac{7}{11}x+9=\frac{3}{11}x-14$ and the equation $\frac{7}{11}x=\frac{3}{11}x+K$
In order to find the value of K that makes both equations equivalent, we must move all constant terms in the first equation to the right side.
For $\frac{7}{11}x+9=\frac{3}{11}x-14$, subtract 9 from both sides.
$\frac{7}{11}x=\frac{3}{11}x-5$.
Therefore, both equations will be equivalent when $K=-23$.
