Answer
$x=-\frac{3}{22}$
Work Step by Step
We are given the equation $7x^{2}+2x-3=6x(x+4)+x^{2}$. We can solve for x by first using the distributive property to simplify the right side.
$7x^{2}+2x-3=6x\times(x+4)+x^{2}=6x^{2}+24x+x^{2}$
Group like terms on the right side.
$7x^{2}+2x-3=7x^{2}+24x$
Subtract $7x^{2}$ from both sides.
$2x-3=24x$
Subtract 2x from both sides.
$-3=22x$
Divide both sides by 22.
$x=-\frac{3}{22}$