Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.2 - An Introduction to Problem Solving - Exercise Set - Page 68: 83

Answer

$25$ skateboards

Work Step by Step

Equating the cost expression, $C=100+20x$, and the revenue expression, $24x,$ then the number of skateboards, $x$, to break even is \begin{array}{l}\require{cancel} 100+20x=24x \\\\ 100=24x-20x \\\\ 100=4x \\\\ \dfrac{100}{4}=x \\\\ x=25 .\end{array} Hence, $\text{ $25$ skateboards }.$
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