Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.3 - Formulas and Problem Solving - Exercise Set - Page 73: 25

Answer

A= for 1: 4,703.71 for 2: 4,713.99 for 4: 4,719.22 for 12: 4,722.74 for 365: 4,724.45

Work Step by Step

Compound Interest Formula: $A=P(1+\frac{r}{n})^{n\times t}$ A= solving for A P=3500 r= turn 3% to decimal = 0.03 n= the values you will replace 1,2,4,12,365 t=10 $A=3500(1+\frac{0.03}{1})^{1\times 10}$ = 4,703.71 $A=3500(1+\frac{0.03}{2})^{2\times 10}$ =4,713.99 $A=3500(1+\frac{0.03}{4})^{4\times 10}$ = 4,719.22 $A=3500(1+\frac{0.03}{12})^{12\times 10}$ =4,722.74 $A=3500(1+\frac{0.03}{365})^{365\times 10}$ =4,724.45
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