Answer
If n=1:$A=11983$ dollars
If n=2:$A=12136$ dollars
If n=4:$A=12216$ dollars
If n=12:$A=12270$ dollars
If n=365:$A=12297$ dollars
Work Step by Step
$A=P(1+\frac{r}{n})^{nt}$
If n=1:
$A=5000(1+\frac{.06}{1})^{1*15}$
$A=11983$
If n=2:
$A=5000(1+\frac{.06}{2})^{2*15}$
$A=12136$
If n=4:
$A=5000(1+\frac{.06}{4})^{4*15}$
$A=12216$
If n=12:
$A=5000(1+\frac{.06}{12})^{12*15}$
$A=12270$
If n=365:
$A=5000(1+\frac{.06}{365})^{365*15}$
$A=12297$
