Answer
$4y^2-1+\dfrac{9}{y-3}$
Work Step by Step
Using the synthetic division method below, then
\begin{array}{l}\require{cancel}
(
4y^3-12y^2-y+12
)\div(
y-3
)
\\=
4y^2-1+\dfrac{9}{y-3}
.\end{array}
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