Answer
$f^{-1}(3)=1$
Work Step by Step
To find $f^{-1}(3)$ means that you have to look for the value of $x$ such that $f(x) = 3$.
To achieve this, substitute 3 to $f(x)$ to have:
$f(x) = x^3+2
\\3 = x^3 + 2
\\3-2 = x^3
\\1=x^3
\\\sqrt[3]{1} = x
\\1=x$
Therefore $f^{-1}(3) = 1$.