Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 550: 12b

Answer

$f^{-1}(2)=0$

Work Step by Step

To find $f^{-1}(2)$ means that you have to look for the value of $x$ such that $f(x) = 2$. To achieve this, substitute 2 to $f(x)$ to have: $f(x) = x^3+2 \\2 = x^3 + 2 \\2-2 = x^3 \\0=x^3 \\0=x$ Therefore $f^{-1}(2) = 0$.
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