Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 53: 74

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow y=-4x-3$ For the vertical intercept plug $x=0$. $\Rightarrow y=-4(0)-3$ Simplify. $\Rightarrow y=-3$ The vertical intercept is $A=(0,-3)$ Slope is $m=-4=\frac{-4}{1}$, so the rise is $-4$ when the run is $1$. Starting at $(0,-4)$ and going down $4$ and over $1$, we get to $B=(1,-7)$. Repeat the same to get the next point $C=(2,-11)$. By using theses three points draw a line.
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