Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 53: 75

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow y=-\frac{7}{5}x+11$ For the vertical intercept plug $x=0$. $\Rightarrow y=-\frac{7}{5}(0)+11$ Simplify. $\Rightarrow y=11$ The vertical intercept is $A=(0,11)$ Slope is $m=\frac{-7}{5}$, so the rise is $-7$ when the run is $5$. Starting at $(0,11)$ and going down $7$ and over $5$, we get to $B=(5,4)$. Repeat the same to get the next point $C=(10,-3)$. By using theses three points draw a line.
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