Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Mid-Chapter Check Point - Page 53: 11

Answer

$x=3$

Work Step by Step

$\frac{3x}{4} - \frac{x}{3} + 1 = \frac{4x}{5} - \frac{3}{20}$ Subtract 1 from both sides: $\frac{3x}{4} - \frac{x}{3} + 1 -1= \frac{4x}{5} - \frac{3}{20} - 1$ $\frac{3x}{4} - \frac{x}{3} = \frac{4x}{5} - \frac{3}{20} - 1$ $\frac{3x}{4} - \frac{x}{3} = \frac{4x}{5} - \frac{3}{20} - \frac{20}{20}$ $\frac{3x}{4} - \frac{x}{3} = \frac{4x}{5} - \frac{23}{20}$ Subtract $\frac{4x}{5}$ from both sides: $\frac{3x}{4} - \frac{x}{3} - \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5} - \frac{23}{20}$ $\frac{3x}{4} - \frac{x}{3} - \frac{4x}{5} = - \frac{23}{20}$ Simplify by multiplying the whole equation with the least common denominator: 4 : 2 x 2 3 : 3 5 : 5 20 : 2 x 2 x 5 Hence, the LCD would be 2 x 2 x 5 x 3 = 60 $(\frac{3x}{4} - \frac{x}{3} - \frac{4x}{5})\times60 = - (\frac{23}{20})\times60$ $45x - 20x - 48x = - 69$ Simplify: $-23x = -69$ Divide both sides by -23: $x = 3$
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