Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Mid-Chapter Check Point - Page 53: 7

Answer

$x=0$

Work Step by Step

$3(2x - 5) - 2(4x + 1) = -5(x + 3) - 2$ Expand $3(2x - 5) = 6x-15$ Expand $2(4x + 1) = 8x + 2$ Expand $-5(x + 3) = -5x - 15$ Rewrite the equation: $6x-15-(8x + 2)=-5x - 15$ Simplify: $6x-15-8x-2=-5x - 15-2$ $-2x-17 = -5x - 17$ Add 17 to both sides: $-2x-17+17 = -5x - 17+17$ $-2x=-5x$ Add 5x to both sides: $-2x+5x=-5x+5x$ $3x=0$ Divide both sides by 3: $x=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.