Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set - Page 15: 126

Answer

$(2\cdot3+3)\cdot 5$

Work Step by Step

Note that $45=9 \cdot 5$. The first three numbers from the left can be grouped together to give: $(2 \cdot 3 + 3) \cdot 5 = (6+3)\cdot5 = 9\cdot 5 = 45$ Thus, the parentheses can be used to enclose the first three numbers to obtain: $=(2\cdot3+3)\cdot 5$
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