Answer
The distance between Mercury and the sun is $ 0.55 $ astronomical unit.
Work Step by Step
The given formula is
$ d=\frac{3(2^{n-2})+4}{10} $
Where, $ d $ is measured in astronomical units and $ n $ is the number of planet from the sun.
Substitute $ n=1 $ into the formula.
$ d=\frac{3(2^{1-2})+4}{10} $
$ d=\frac{3(2^{-1})+4}{10} $
$ d=\frac{3 \cdot \frac{1}{2}+4}{10} $
$ d=\frac{ \frac{3}{2}+4}{10} $
$ d=\frac{ \frac{3+8}{2}}{10} $
$ d=\frac{ \frac{11}{2}}{10} $
$ d=\frac{11}{20} $
$ d=0.55 $
