Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 81: 148

Answer

The statement does not make sense. $25(x^{3})^{9} \ne25x^{12}$

Work Step by Step

To determine whether or not the statement makes sense, evaluate all the given equations. 1. $(5x^{6})^{2}$ Products to Powers rule: $(ab)^{n} = a^{n}\cdot b^{n}$ Thus, $$(5x^{6})^{2}$$ $$= (5^{2}x^{6\cdot 2})$$ $$=25x^{12}$$ 2. $(5x^{3})(5x^{9})$ Recall the product rule: $a^{m}⋅a^{n}=a^{m+n}$ Thus, $$(5x^{3})(5x^{9})$$ $$=25x^({3+9})$$ $$=25x^{12}$$ 3. $25(x^{3})^{9}$ Recall the power rule: $(a^{m})^{n}=a^{mn}$ Thus, $$25(x^{3})^{9}$$ $$=25x^{(3\cdot 9)}$$ $$=25x^{27}$$ 4. $5^{2}(x^{2})^{6}$ Using the power rule, $$5^{2}(x^{2})^{6}$$ $$=25x^{(2\cdot 6)}$$ $$=25x^{12}$$ Since not all the given expressions are equal to $25x^{12}$, therefore the statement does not make sense.
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