Answer
$\displaystyle \frac{27}{35}$ is a solution.
Work Step by Step
For the given number to be a solution of the equation,
the equation must hold true when we substitute the variable with the given number.
Multiplication comes before addition,
you can divide numerators and denominators by common factors before performing multiplication.
LHS=$ \displaystyle \frac{2}{9\div 9}\cdot\frac{27\div 9}{35}+\frac{1}{3\div 3}\cdot\frac{27\div 3}{35}$
$=\displaystyle \frac{2\cdot 3}{35}+\frac{9}{35}$
$=\displaystyle \frac{15\div 5}{35\div 5}$
$=\displaystyle \frac{3}{7}$
LHS = RHS, so $\displaystyle \frac{27}{35}$ is a solution.
