Answer
26 is not a solution.
Work Step by Step
For the given number to be a solution of the equation,
the equation must hold true when we substitute the variable with the given number.
$LHS=\displaystyle \frac{1}{3}(26-2)=\frac{24}{3}=\frac{24\div 3}{3\div 3}=\frac{8}{1}=8$
$RHS=\displaystyle \frac{1}{5}(26+4)+3$
$=\displaystyle \frac{30}{5}+3$
$=\displaystyle \frac{30\div 5}{5\div 5}+3$
$=\displaystyle \frac{6}{1}+3$
$=6+3$
$=9$
$LHS\neq RHS$ , so 26 is not a solution.
