Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.2 Exercises - Page 23: 26

Answer

See the solution.

Work Step by Step

The reduced row echelon form of the augmented matrix is $\left[ \begin{array}{cccc} 1 & 0 & 0 &a_1\\ 0 & 1&0&a_2\\ 0&0&1&a_3 \end{array} \right],$ where $a_1$, $a_2$, and $a_3$ are numbers. We can see the last column (on the right) is not a pivot column and the corresponding system of equations will have no free variables. Hence the system is consistent and has a unique solution. Alternatively, you can say that there is a pivot in each column, meaning there are no free variables.
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