Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.2 Exercises - Page 23: 33

Answer

$$p(t)=7+6t-t^2$$

Work Step by Step

The system can be writen in this augmented form: $$\left[\begin{array}{rrr} 1 &1 &1^2 &12 \\ 1 &2 & 2^2 & 15 \\ 1 &3 & 3^2 & 16 \end{array}\right]$$ By calculation, the reduced echelon form is: $$\left[\begin{array}{rrr} 1 &0 &0 &7 \\ 0 &1 & 0 & 6 \\ 0 &0 & 1 & -1 \end{array}\right]$$ The solution is $(7,6,-1)$, which corresponds to $(a_0,a_1,a_2)$. Substitute $(a_0,a_1,a_2)$ with $(7,6,-1)$ in $p(t)=a_0+a_1t+a_2t^2$.
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