Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.1 Exercises - Page 102: 3

Answer

$3I_2-A$(-1 1 \ -5 5) $(3I_2)A$=(12 -3 \ 15 -6)

Work Step by Step

$3I_2-A$=(3 0 \ 0 3)-(4 -1 \ 5 -2)=(-1 1 \ -5 5) $(3I_2)A$=(3 0 \ 0 3)(4 -1 \ 5 -2)=(12+0 -3+0 \ 0+15 0-6)=(12 -3 \ 15 -6)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.