Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.1 Exercises - Page 102: 5

Answer

$\begin{bmatrix}-7&4\\7&-6\\12&-7\end{bmatrix}$

Work Step by Step

(a)$ \begin{align} AB&=\begin{bmatrix}A\begin{bmatrix}3\\-2\end{bmatrix} &A\begin{bmatrix}-2\\1\end{bmatrix}\end{bmatrix}\\ &=\begin{bmatrix}3\begin{bmatrix}-1\\5\\2\end{bmatrix}-2\begin{bmatrix}2\\4\\-3\end{bmatrix}&(-2)\begin{bmatrix}-1\\5\\2\end{bmatrix}+1\begin{bmatrix}2\\4\\-3\end{bmatrix}\end{bmatrix}\\ &=\begin{bmatrix}-3-4&2+2\\15-8&-10+4\\6+6&-4-3\end{bmatrix}\\ &=\begin{bmatrix}-7&4\\7&-6\\12&-7\end{bmatrix} \end{align} $ (b)$ \begin{align} AB&=\begin{bmatrix}(-1)(3)+(2)(-2)&(-1)(-2)+(2)(1)\\ (5)(3)+(4)(-2)&(5)(-2)+(4)(1)\\(2)(3)+(-3)(-2)&(2)(-2)+(-3)(1)\end{bmatrix}\\ &=\begin{bmatrix}-3-4&2+2\\15-8&-10+4\\6+6&-4-3\end{bmatrix}\\ &=\begin{bmatrix}-7&4\\7&-6\\12&-7\end{bmatrix} \end{align} $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.