Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.1 Exercises - Page 103: 21

Answer

Because there is a linear combination of A such that it is 0, the columns of A are linearly dependent We know that the right-most column of A is all zero.

Work Step by Step

Here is a generalized depiction. Suppose \[ A= \left[ {\begin{array}{cc} l & m \\ n & p \\ \end{array} } \right] \] and \[ B= \left[ {\begin{array}{cc} a & b \\ c & d \\ \end{array} } \right] \] Then \[ AB= \left[ {\begin{array}{cc} la+mc & md+lb \\ na+pc & nb+pd \\ \end{array} } \right] \] Every value of A must be 0. For the second column of AB to be 0, we have a system of equations: 0=md+lb 0=nb+pd 0=(m+p)d+(l+n)b. Neither b nor d is 0. We can declare that the sum of the values in each column are either all 0 or that the sums of the values for each column must be equal and opposite of the other.
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