Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.1 Functions - Exercises Set 0.1 - Page 13: 16

Answer

Yes. $$y=- \sqrt{25-x^2}$$

Work Step by Step

Yes, it is a function since there exists no real number for which there are two distinct values of $y$. This graph is the negative section of the circle$$x^2+y^2=25 \quad \Rightarrow \quad y= \pm \sqrt{25-x^2},$$so the function representing this section is $$y=-\sqrt{25-x^2}.$$
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