Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.1 Functions - Exercises Set 0.1 - Page 14: 28

Answer

$f(x)=\begin{cases} -2x+8,\text{ for } x\lt \frac{5}{2}\\ 2x-2\text{ for } x\geq \frac{5}{2} \end{cases}$

Work Step by Step

We are given the function: $f(x)=3+|2x-5|$ Rewrite the function in piecewise form, using the fact that $|y|=-y$ for $y\lt 0$ and $|y|=y$ for $y\geq 0$: $f(x)=\begin{cases} 3-(2x-5),\text{ for } 2x-5\lt 0\\ 3+(2x-5)\text{ for } 2x-5\geq 0 \end{cases}$ $f(x)=\begin{cases} 3-2x+5,\text{ for } 2x\lt 5\\ 3+2x-5\text{ for } 2x\geq 5 \end{cases}$ $f(x)=\begin{cases} -2x+8,\text{ for } x\lt \frac{5}{2}\\ 2x-2\text{ for } x\geq \frac{5}{2} \end{cases}$
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