Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.3 Families Of Function - Exercises Set 0.3 - Page 38: 38

Answer

$\{-1.895,0,1.895\}$

Work Step by Step

We are given the equation: $x=2\sin x$ One obvious solution is $x=0$ Because $-1\leq \sin x\leq 1$, we have: $-2\leq\sin x\leq 2$ $-2\leq x\leq 2$ So, if there are other solutions, they are in the interval $[-2,2]$. The function $y=x$ is increasing on $[0,2]$, having $y=2$ for $x=2$. The function $y=2\sin x$ is increasing on $\left[0,\dfrac{\pi}{2}\right]$, when $2\sin\dfrac{\pi}{2}=2$, and decreasing on $\left[\dfrac{\pi}{2},2\right]$. Therefore, the two graphs must intersect once in the interval $\left[\dfrac{\pi}{2},2\right]$. Because of symmetry, the same goes for the interval $[-2,0]$. So the equation has 3 solutions. We use a graphing utility to approximate them: $\{-1.895,0,1.895\}$
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