Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.4 Inverse Functions - Exercises Set 0.4 - Page 44: 1

Answer

Q:1 (a): Yes (b): No (c): Yes (d): No

Work Step by Step

According to 0.4.1 Definition: "If the functions f and g satisfy the two conditions g(f(x)) = x for every x in the domain of f f(g(y)) = y for every y in the domain of g then we say that f is an inverse of g and g is an inverse of f or that f and g are inverse functions. (a): Yes Explanation: Given that f(x)=4x and g(x)=1/4(x) = 4/x f(g(x)) = 4(x/4) =x, g(f(x)) = (4x)/4 =x So, f and g are inverse functions. (b): No Explanation: Given that f(x)=3x+1 and g(x)= 3x-1 f(g(x)) = 3(3x-1)+1 = 9x ,which is not equal to x So, f and g are not inverse functions. (c): Yes Explanation: Given that f(x)=\sqrt[3] (x-2) and g(x)= x^{3}+ 2 f(g(x)) = \sqrt[3] ((x^{3}+2)-2) =x, g(f(x)) = \sqrt[3] (x-2)^{3} =x So, f and g are inverse functions. (d): No Explanation: Given that f(x)= x^{4} and g(x)= \sqrt[4] x f(g(x)) = \sqrt[4] x^{4} ,which is not equal to x So, f and g are not inverse functions.
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