Answer
$f^{-1}(x)$ = $\sqrt[3] \frac{x + 5}{3} $.
Work Step by Step
1. Switch $f^{}(x)$ and $x^{}$.
x = 3*$(y)^3$ - 5
*Lets call f(x) by "y" to simplificate.
2. Isolate "y".
x + 5 = 3$y^{3}$
$y^{3}$ = $\frac{x + 5}{3}$
y = $\sqrt[3] \frac{x + 5}{3} $.
3. Rename y as $f^{-1}(x)$
$f^{-1}(x)$ = $\sqrt[3] \frac{x + 5}{3} $.
