Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - Chapter 0 Review Exercises - Page 47: 16

Answer

$g(x) = x^2 + 2x$

Work Step by Step

$f(x) = 2x + 1$, $h(x) = 2x^2 + 4x + 1$ $f (g(x)) = h(x)$ $2(g(x)) + 1 = 2x^2 + 4x + 1$ $2(g(x)) = 2x^2 + 4x + 1 - 1$ $g(x) = \frac{2x^2 + 4x}{2} = x^2 + 2x$
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