Answer
$ \frac{3}{-5}$
Work Step by Step
$\frac{\lim\limits_{x \to +\infty} 3}{\lim\limits_{x \to +\infty} g (x)} $
Replace the “g(x)” with (-5)
$\frac{\lim\limits_{x \to +\infty} 3}{\lim\limits_{x \to +\infty} g(x)} = \frac{\lim\limits_{x \to +\infty} 3}{\lim\limits_{x \to +\infty} -5} $
The limits cancel each other
$= \frac{3}{-5 } $