Answer
L=1
$\delta=0.002$
Work Step by Step
$\lim\limits_{x \to 2} (x^2-3)$
In order to determine the limit $L$ we plug $x=2$ into $f(x)$, where $f(x)=x^2-3$:
$\lim\limits_{x \to 2} (x^2-3)=2^2-3=4-3=1$
Therefore $L=1$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.2 Exercises - Page 56: 35
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