Answer
False since $$2 \neq 0$$
Work Step by Step
First off, it is best to let the following occur:
f(x)=$$\left\{\begin{matrix}
x-4 & if & x\neq 0\\
0 & if & x=2
\end{matrix}\right.$$
Secondly, when it comes to $f(2)$, it already notes that $x=2$ when $f(x)=0$, which means the following: $$f(2)=0$$
Finally, when it comes to the limitations, it is based on when $x$ is actually approaching $2$, which means $x\rightarrow 2$, which can be simplified as the following:
$$\begin{matrix}
_{x\rightarrow 2}^{\lim}\textrm{f(x)}&x-4&\\
&=(2)-4&\\
&=2-4&\\
&=-2&\neq 0
\end{matrix}$$