Answer
$f(x)$ is continuous for all values of x and has no discontinuities.
Work Step by Step
$x^2+1=0\to x^2=-1$ which has no real solution.
The denominator can never be zero, and the function is defined and continuous for all x.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 80: 40
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
