Answer
$f(x)$ is continuous over the interval $[0, \infty)$
Work Step by Step
The only restriction on $f(x)$ is the radicand of $\sqrt{x}$ not being negative hence $x\ge0\to f(x)$ is continuous over the interval $[0, \infty).$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 80: 79
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