Answer
1, $AB ≅ BC$ All sides of a rhombus are congruent
2. $AE ≅ EC$ Since a rhombus is a parallelogram, its diagonals bisect each other
3. $BE ≅ BE$ All sides are congruent to themselves
4. $ΔAEB ≅ ΔCEB$ Side-side-side congruence
5. $∠AEB ≅ ∠CEB$ Corresponding angles are congruent
6. $∠AEB$ and $∠CEB$ are supplementary angles
7. $EB ⟂ AC$ since the angles formed are supplementary and congruent
Therefore the diagonals of a rhombus intersect at right angles
Work Step by Step
First, we can prove that the triangles created by the diagonals of the rhombus are congruent using information we already know about a rhombus. After that we can prove that the diagonals intersect at right angles.