Answer
$4a $
Work Step by Step
\begin{align*}
\lim _{h \rightarrow 0}\frac{2(a+h)^2-2a^2}{h}&= \lim _{h \rightarrow 0}\frac{2(a^2+h^2+2ah)-2a^2}{h}\\
&= \lim _{h \rightarrow 0}\frac{2h^2+4ah}{h}\\
&=\lim _{h \rightarrow 0} 2h +4a \\
&=4a.
\end{align*}