Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 94: 26

Answer

$5$

Work Step by Step

\begin{align*} \lim _{\theta \rightarrow 0} \frac{ \sin 5\theta}{ \theta}&=5\lim _{5\theta \rightarrow 0} \frac{ \sin 5\theta}{5\theta}\\ &=5(1)=5 \end{align*} Where we used, $\lim _{x\rightarrow 0}\frac{ \sin x}{ x}=1. $
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