Answer
$-\dfrac {1}{8}$
Work Step by Step
$\lim _{s\rightarrow 16}\dfrac {4-\sqrt {s}}{s-16}=\dfrac {-\left( \sqrt {s}-4\right) }{\left( \sqrt {s}-4\right) \left( \sqrt {s}+4\right) }=-\dfrac {1}{\sqrt {s}+4}=-\dfrac {1}{8}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 35
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
