Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises - Page 97: 43

Answer

$f(-3)=-2$ $f(0)=0$ $f(-2)=-1$

Work Step by Step

The given pice-wise function is; $f(x)$=${ \begin{cases} x+1 & \text{if $x \le-1$} \\ x^2 & \text{if $x >-1$} \end{cases} }$ for, $x=-3$ then, $f(-3)=-3+1$ $f(-3)=-2$ for $x=0$ $f(0)=(0)^2$ $=(0)$ $f(0)=0$ For $x=-2$ $f(-2)=-2+1$ $=0$ $f(-2)=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.