Answer
TRUE
Work Step by Step
TRUE
$\lim\limits_{x \to 3}{\frac{x^2-9}{x-3}}=\lim\limits_{x \to 3}{\frac{(x-3)(x+3)}{(x-3)}}=\lim\limits_{x \to 3}{\frac{(x+3)}{1}}=\lim\limits_{x \to 3}{(x+3)}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - Review - True-False Quiz - Page 95: 11
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