Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.6 Cylinders and Quadric Surfaces - 12.6 Exercises - Page 880: 11

Answer

Elliptic Paraboloid

Work Step by Step

\[ x = y^2 + 4z^2 \] Evaluated at \(x = 0\): \[ y^2 + 4z^2 = 0 \\ x = 0 \quad \text{and} \quad y = 0 \] Evaluated at \(x = 4\): \[ y^2 + 4z^2 = 4 \\ \frac{y^2}{4} + \frac{4z^2}{4} = 1 \\ \frac{y^2}{2^2} + \frac{z^2}{1^2} = 1 \] Ellipse with radius 1 on \(z\)-axis and 2 on \(x\)-axis. Another way of solving is that it follows the standard formula of the Elliptic Paraboloid: \[ \frac{z}{c} = \frac{x^2}{a^2} + \frac{y^2}{b^2} \] In this case, the paraboloid is oriented along the \(x\)-axis (instead of the \(z\)-axis as in the standard form).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.