Answer
\[
z=\sqrt{x^2+y^2} \quad Red \\
x^2+y^2=1 \quad Blue
\]
Work Step by Step
\[
z=\sqrt{x^2+y^2} \quad Red \\
x^2+y^2=1 \quad Blue
\]
See graph.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 12 - Vectors and the Geometry of Space - 12.6 Cylinders and Quadric Surfaces - 12.6 Exercises - Page 880: 43
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