Answer
Let $(x_0,y_0,_0)$ be a point on the line and $ \lt a,b,c\gt$ be a direction vector of the line.
Equation of the line is given by $r=r_0+tv$
Parametric equations are defined as:
$x=x_0+at$, $y=y_0=bt$ and $z=z_0+ct$
The symmetric equations are defined as:
$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$
Work Step by Step
Let $(x_0,y_0,_0)$ be a point on the line and $ \lt a,b,c\gt$ be a direction vector of the line.
Equation of the line is given by $r=r_0+tv$
Parametric equations are defined as:
$x=x_0+at$, $y=y_0=bt$ and $z=z_0+ct$
The symmetric equations are defined as:
$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$